python - Sqlite3 List index out of range when trying to get LIKE Query -


i'm trying execute following code:

conn = sqlite3.connect("./databases/functions/he.db") cursor = conn.cursor()  sql = "select * requests request ?" cursor.execute(sql, [(msg)]) results = cursor.fetchall()[0] print results  if((results)[1] == "true"):     gpio = (results)[2]     direction = (results)[3]     print "gpio setup ready.."

and i'm getting following error:

file "./functions/dofunctions.py", line 29, in enrequests results = cursor.fetchall()[0] indexerror: list index out of range

i'm messing database, , fixing problems, don't know why pop beginning..

the code getting msg string, searching if exist on database, if taking gpio pin , sending signal (request @ index 0 in database row while gpio pin @ index 2).

your query returned 0 results, there no first row fetch. .fetchall() returns empty list in case, , there no item @ index 0.

if interested in first result of query, should use .fetchone() instead:

results = cursor.fetchone()

.fetchone() either returns row, or none if there no matching results.

you using redundant parenthesis in query; not cause of problem, can safely remove them:

cursor.execute(sql, [msg])

or use tuple:

cursor.execute(sql, (msg,))

you in several places, can cut out lot of (...) in code without effect other improved readability. adding in test if there are results .fetchone() call code be:

if results , results[1] == "true":     gpio = results[2]     direction = results[3]     print "gpio setup ready.."

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