php - Updating one drop down menu according to option selected in another drop down menu from database -


edited after suggestions (still unresolved):

i have 2 drop down menu's, 1 called country, , other called city. when user chooses country country drop down menu (hereafter drop down menu referred ddm brevity), want city ddm show cities in particular country.

i have relation (called location) in database of following simple form (with entries):

id country city     1  india  new delhi     2  india  hyderabad     3   usa    san diego     4   usa    palo alto

this code wrote : 

<html> <head> <title>admin page</title> </head>  <script type="text/javascript" src="http://ajax.googleapis.com/ ajax/libs/jquery/1.4.2/jquery.min.js"></script>  <script type="text/javascript">     $(document).ready(function()     {         $(".country").change(function()         {             var country=$(this).val();             var datastring = 'country='+ country;             alert(datastring);             $.ajax             ({                 type: "post",                 url: "getcity.php",                 data: datastring,                 datatype : html,                 cache: false,                 success: function(data, textstatus)                 {                     alert(textstatus);                     $(".city").html(data);                 }              });          });     }); </script>  <body>  <br /> <legend><h2>welcome admin!</h2></legend>   <?php include('db.php');  $sql="select distinct country location";  $result=mysqli_query($con, $sql);   if (!$result) {     echo "db error, not list tables\n";     echo 'mysql error: ' . mysql_error();     exit; }  echo '<h4>location :</h4>'; echo '<select name="loaction" class="location">'; echo '<option value="foo">'.'choose country'.'</option>'; while ($row=mysqli_fetch_array($result)) {     echo '<option value='.$row[country].'>'.$row[country].'</option>'; } echo '</select>';  ?>  <h4><label>city :</label> </h4> <select name = 'city' class = 'city'>     <option value = 'foo' > choose city </option> </select>

i hope have taken trouble scroll down , see above code. file getcity.php follows :

<?php include('db.php');  if($_post['country']) {     $country=$_post['country'];     $sql=mysql_query("select id, city location country='$country'");      while($row=mysql_fetch_array($sql))     {         $id=$row['id'];         $city=$row['city'];         echo '<option value="'.$id.'">'.$city.'</option>';     } }

however, cannot see in city ddm after status returned ajax call (seen through alert()) 'success'.

what missing?

thanks again.

here's how i'm doing it:

you need 2 selectors:

<select name="state" class="stateselector" ></select> <select name="city" class="cityselector" ></select>

and jquery ajax (get) call, fire every time selector of stateselector class changes:

$('.stateselector').change(function(){     $.getjson("http://site.com/getcities/"+$(this).val()+"/all",{}, function(j){         var options = '<option value="0">- city -</option>';         (var = 0; < j.length; i++) {             options += '<option value="' + j[i].id + '">' + j[i].name + '</option>';         }         $('.cityselector').html(options);         $('.cityselector').prop("selectedindex", 0);     }); });

at server side, need call url (http://site.com/getcities/{stateid}) receive state id , return json collection cities particular state, in example json structure has id (j[i].id) , name (j[i].name).


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