Is there another better way to get file ext from a given path in python -


i'm new in python, know, can file ext path use:

os.path.splitext(path)[1][1:]

this works well, seems not quite beautiful, want ask: there better way file ext

the readable way be

name, ext = os.path.splitext(path) ext = ext[1:]

though that's no longer single expression. if want single expression, wrap in function:

def extension(path):     name, ext = os.path.splitext(path)     return ext[1:]

be aware on systems, files may have empty extension, e.g.

>>> os.path.splitext('ham.') ('ham', '.')

and you're treating same files no extension @ (just ham). usually, difference doesn't matter, in cases might, why splitext works way does.


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