java - Compare two XML strings ignoring element order -


support have 2 xml strings

<test>   <elem>a</elem>   <elem>b</elem> </test>  <test>   <elem>b</elem>   <elem>a</elem> </test>

how write test compares 2 strings , ignores element order?

i want test short possible, no place 10-line xml parsing etc. i'm looking simple assertion or smt similar.

i have (which doesnt work)

   diff diff = xmlunit.comparexml(expectedstring, actualstring);       xmlassert.assertxmlequal("meh", diff, true); 

public static document loadxmlfromstring(string xml) throws exception {     documentbuilderfactory factory = documentbuilderfactory.newinstance();     documentbuilder builder = factory.newdocumentbuilder();     inputsource = new inputsource(new stringreader(xml));     return builder.parse(is); }  @test public void test() throws exception {     document doc = loadxmlfromstring("<test>\n" +             "  <elem>b</elem>\n" +             "  <elem>a</elem>\n" +             "</test>");     xpathfactory xpathfactory = xpathfactory.newinstance();     xpath xpath = xpathfactory.newxpath();     xpathexpression expr = xpath.compile("//test//elem");     nodelist = (nodelist) expr.evaluate(doc, xpathconstants.nodeset);     set<string> values = new hashset<>();     if (all != null && all.getlength() > 0) {         (int = 0; < all.getlength(); i++) {             values.add(all.item(i).gettextcontent());         }     }     set<string> expected = new hashset<>(arrays.aslist("a", "b"));     assertequals(expected, values); }

and compare sets


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