scala - Regex parse a list of comma separated number ranges, and capture them in individual groups -

i found the following regex matching comma separated numbers or ranges of numbers:

val reg = """^(\d+(-\d+)?)(,\s*(\d+(-\d+)?))*$""".r 

while does match valid strings, one string out of it, instead of a list of strings, each corresponding 1 of separated entries. e.g.

reg.findallin("1-2, 3").map(s => s""""$s"""").tolist 

gives

list("1-2, 3") 

but want:

list("1-2", "3") 

---

the following comes closer:

val list = "1-2, 3" match {   case reg(groups @ _*) => groups   case _ => nil }  list.map(s => s""""$s"""") 

but contains sorts of 'garbage':

list("1-2", "-2", ", 3", "3", "null") 

with findallin should not try match entire string. split biggest continuos match can find. instead need part of regex:

val reg = """(\d+(-\d+)?)""".r 

if use findallin return need.

scala> val x = """(\d+(-\d+)?)""".r x: scala.util.matching.regex = (\d+(-\d+)?)  scala> x.findallin("1-2, 3").tolist res0: list[string] = list(1-2, 3)