python - Iterating over a list and joining items of same type -

i have bunch of strings shoved lists via list(string):

stringy = "i've 24got 697love-a-ly2 bunch of 000coconuts!" listy = list(stringy) 

where listy looks like:

['i', "'", 'v', 'e', ' ', '2', '4', 'g', 'o', 't', ' ', 'a', ' ', '6', '9'... 

i'm looking cleaner way iterate through list and, without throwing out of individual character entries, join of integers produce:

['i', "'", 'v', 'e', ' ', '24', 'g', 'o', 't', ' ', 'a', ' ', '697','l','o'... 

where integers going in strings not predictable, , number of digits in number not predictable (i run 1 or 1000000000.)

to find integer values in first place thought like:

for in listy:     if i.isdigit():         x = listy.index(i)         z = listy[x+1]         if z.isdigit(): 

...but that's going inefficient bloody mess.

actually putting numbers going pretty easy having trouble coming neat way check each number. suggestions?

you can pretty using re,

>>> import re >>> = "i've 24got 697love-a-ly2 bunch of 000coconuts!" >>> re.findall(r'\d+|.', a) ['i', "'", 'v', 'e', ' ', '24', 'g', 'o', 't', ' ', 'a', ' ', '697', 'l', 'o', 'v', 'e', '-', 'a', '-', 'l', 'y', '2', ' ', 'b', 'u', 'n', 'c', 'h', ' ', 'o', 'f', ' ', '000', 'c', 'o', 'c', 'o', 'n', 'u', 't', 's', '!'] 

if doing operation multiple times should consider compiling like,

>>> splitter = re.compile(r'\d+|.')