python - How to find elements existing in two lists but with different indexes -

i have 2 lists of same length contains variety of different elements. i'm trying compare them find number of elements exist in both lists, have different indexes.

here example inputs/outputs demonstrate mean:

>>> compare([1, 2, 3, 4], [4, 3, 2, 1]) 4 >>> compare([1, 2, 3], [1, 2, 3]) 0 # each item in first list has same index in other >>> compare([1, 2, 4, 4], [1, 4, 4, 2]) 2 # 3rd '4' in both lists don't count, since have same indexes >>> compare([1, 2, 3, 3], [5, 3, 5, 5]) 1 # duplicates don't count 

the lists same size.

this algorithm have far:

def compare(list1, list2):     # eliminate direct matches     list1 = [a (a, b) in zip(list1, list2) if != b]     list2 = [b (a, b) in zip(list1, list2) if != b]      out = 0     possible in list1:         if possible in list2:             index = list2.index(possible)             del list2[index]             out += 1     return out 

is there more concise , eloquent way same thing?

this python function hold examples provided:

def compare(list1, list2):     d = {e:i i, e in enumerate(list1)}     return len(set(e i, e in enumerate(list2) if d.get(e) not in (none, i)))