sorting list of dictionnaries in python -


i have list :

l = [{'status': 1, 'country': 'france'}, {'status': 1, 'country': 'canada'}, {'status': 1, 'country': 'usa'}]

how sort list country (or status) elements, asc/desc.

use list.sort() sort list in-place or sorted new list:

>>> l = [{'status': 1, 'country': 'france'}, {'status': 1, 'country': 'canada'}, {'status': 1, 'country': 'usa'}] >>> l.sort(key= lambda x:x['country']) >>> l [{'status': 1, 'country': 'france'}, {'status': 1, 'country': 'canada'}, {'status': 1, 'country': 'usa'}]

you can pass optional key word argument reverse = true sort , sorted sort in descending order.

as upper-case alphabet considered smaller it's corresponding smaller-case version(due ascii value), may have use str.lower well.

>>> l.sort(key= lambda x:x['country'].lower()) >>> l [{'status': 1, 'country': 'canada'}, {'status': 1, 'country': 'france'}, {'status': 1, 'country': 'usa'}]

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